Today, we are going to have a puzzle about Pirates who had gone for the search of Gold coins.
There were five pirates in all and each one was of different age than others. With, the luck favouring and their hard work, they were able to get a hundred Gold Coins. But, the moment they were returning to the shore, they started fighting on who got how many gold coins. Some said, they had worked harder and found more gold coins than others, so they were supposed to get more than those who hadn't worked with their complete capabilities.
So, to solve this conflict, they decided to split the coins using this scheme.
The oldest and the wisest pirate suggested that all pirates would vote for or against the sharing of the coins. If the pirate suggesting the sharing gets 50% or more agreement, then the coins will be shared that way. If the pirate suggesting the scheme gets less than 50% agreement in voting, that pirate will be thrown in the sea and then the same procedure will be carried on with the remaining pirates. As, pirates are thirsty for blood, if they are getting the same amount of gold coins in both the cases - voting for the acceptance of the scheme as well as voting against the scheme, then that pirate will vote against the procedure, as in that case, he gets to throw a pirate in the sea. Now, the sequence of suggesting the schemes will be from oldest to youngest.
Now, assume that all these pirates are wise, smart and completely logical towards their profits. And definitely no one wants to die. Then, what will be the outcome of this process? How many pirates will die and how many will stay alive? What are the number of gold coins, everyone will get in the accepted scheme?
The puzzle demands more of a logic than several other puzzles. I have rated this puzzle in one of the toughest puzzles. I recommend you all to try your best to come up with the answer by yourself. The puzzle is completely logical but a bit tough.
Several other tough puzzles, from my blog:
Bodmas and his students
Apples
There were five pirates in all and each one was of different age than others. With, the luck favouring and their hard work, they were able to get a hundred Gold Coins. But, the moment they were returning to the shore, they started fighting on who got how many gold coins. Some said, they had worked harder and found more gold coins than others, so they were supposed to get more than those who hadn't worked with their complete capabilities.
So, to solve this conflict, they decided to split the coins using this scheme.
The oldest and the wisest pirate suggested that all pirates would vote for or against the sharing of the coins. If the pirate suggesting the sharing gets 50% or more agreement, then the coins will be shared that way. If the pirate suggesting the scheme gets less than 50% agreement in voting, that pirate will be thrown in the sea and then the same procedure will be carried on with the remaining pirates. As, pirates are thirsty for blood, if they are getting the same amount of gold coins in both the cases - voting for the acceptance of the scheme as well as voting against the scheme, then that pirate will vote against the procedure, as in that case, he gets to throw a pirate in the sea. Now, the sequence of suggesting the schemes will be from oldest to youngest.
Now, assume that all these pirates are wise, smart and completely logical towards their profits. And definitely no one wants to die. Then, what will be the outcome of this process? How many pirates will die and how many will stay alive? What are the number of gold coins, everyone will get in the accepted scheme?
The puzzle demands more of a logic than several other puzzles. I have rated this puzzle in one of the toughest puzzles. I recommend you all to try your best to come up with the answer by yourself. The puzzle is completely logical but a bit tough.
Several other tough puzzles, from my blog:
Bodmas and his students
Apples
No comments:
Post a Comment